(3x+4/x^2+14x+48)-(2x-4/x^2+14x+48)

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Solution for (3x+4/x^2+14x+48)-(2x-4/x^2+14x+48) equation:


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

3*x+14*x-(2*x)-(14*x)+4/(x^2)+4/(x^2)-48+48 = 0

3*x+14*x-2*x-14*x+4/(x^2)+4/(x^2)-48+48 = 0

1*x^1+8*x^-2 = 0

(1*x^3+8*x^0)/(x^2) = 0 // * x^4

x^2*(1*x^3+8*x^0) = 0

x^2

x^3+8 = 0

{ 1, -1, 2, -2, 4, -4, 8, -8 }

1

x = 1

x^3+8 = 9

1

-1

x = -1

x^3+8 = 7

-1

2

x = 2

x^3+8 = 16

2

-2

x = -2

x^3+8 = 0

-2

x+2

x^2-2*x+4

x^3+8

x+2

-x^3-2*x^2

8-2*x^2

2*x^2+4*x

4*x+8

-4*x-8

0

x^2-2*x+4 = 0

DELTA = (-2)^2-(1*4*4)

DELTA = -12

DELTA < 0

x in { -2}

x = -2

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